1.

With usual notation, if in a triangle ABC, cosAcosB+sinAsinBsinC=1, then a:b:c=x:x:y. The value of 2√2y is

Answer» With usual notation, if in a triangle ABC, cosAcosB+sinAsinBsinC=1, then a:b:c=x:x:y. The value of 22y is


Discussion

No Comment Found