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With usual notation, if in a triangle ABC, cosAcosB+sinAsinBsinC=1, then a:b:c=x:x:y. The value of 2√2y is |
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Answer» With usual notation, if in a triangle ABC, cosAcosB+sinAsinBsinC=1, then a:b:c=x:x:y. The value of 2√2y is |
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