InterviewSolution
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Without actually performing the long division, state whether the following rational numbers will have a terminating decimal expansion or a non-terminating repeating decimal expansion.(i) \(\frac{23}{8}\)(ii) \(\frac{125}{441}\)(iii) \(\frac{35}{50}\)(iv) \(\frac{77}{210}\)(v) \(\frac{129}{(2^2 \times 5^7 \times 7^{17})}\)(vi) \(\frac{987}{10500}\) |
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Answer» (i) \(\frac{23}{8}\) We have, \(\frac{23}{8}\) and here the denominator is 8. ⇒ 8 = 23 x 5 We see that the denominator 8 of \(\frac{23}{8}\) is of the form 2m x 5n, where m, n are non-negative integers. Hence, \(\frac{23}{8}\) has terminating decimal expansion. And, the decimal expansion of \(\frac{23}{8}\) terminates after three places of decimal. (ii) \(\frac{125}{441}\) We have, \(\frac{125}{441}\) and here the denominator is 441. ⇒ 441 = 32 x 72 We see that the denominator 441 of \(\frac{125}{441}\) is not of the form 2m x 5n, where m, n are non-negative integers. Hence, \(\frac{125}{441}\) has non-terminating repeating decimal expansion. (iii) \(\frac{35}{50}\) We have, \(\frac{35}{50}\) and here the denominator is 50. ⇒ 50 = 2 x 52 We see that the denominator 50 of \(\frac{35}{50}\) is of the form 2m x 5n, where m, n are non-negative integers. Hence, \(\frac{35}{50}\) has terminating decimal expansion. And, the decimal expansion of \(\frac{35}{50}\) terminates after two places of decimal. (iv) \(\frac{77}{210}\) We have, \(\frac{77}{210}\) and here the denominator is 210. ⇒ 210 = 2 x 3 x 5 x 7 We see that the denominator 210 of \(\frac{77}{210}\) is not of the form 2m x 5n, where m, n are non-negative integers. Hence, \(\frac{77}{210}\) has non-terminating repeating decimal expansion. (v) \(\frac{129}{(2^2 \times 5^7 \times 7^{17})}\) We have, \(\frac{129}{(2^2 \times 5^7 \times 7^{17})}\) and here the denominator is 22 x 57 x 717. Clearly, We see that the denominator is not of the form 2m x 5n, where m, n are non-negative integers. And hence, \(\frac{129}{(2^2 \times 5^7 \times 7^{17})}\) has non-terminating repeating decimal expansion. (vi) \(\frac{987}{10500}\) We have, \(\frac{987}{10500}\) But, \(\frac{987}{10500}\) = \(\frac{47}{500}\) (reduced form) And now the denominator is 500. ⇒ 500 = 22 x 53 We see that the denominator 500 of \(\frac{47}{500}\) is of the form 2m x 5n, where m, n are non-negative integers. Hence, \(\frac{987}{10500}\) has terminating decimal expansion. And, the decimal expansion of \(\frac{987}{10500}\) terminates after three places of decimal. |
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