Without adding, find the sum (1+3+5+7+9+11+13).

1.	Without adding, find the sum (1+3+5+7+9+11+13).
Answer» Given (1+3+5+7+9+11+13) According to the property of perfect square, for any natural number n, we have sum of first n odd natural numbers = n²But here n = 7 Applying the above law we get Therefore (1+3+5+7+9+11+13) = 7²= 49

Answer»

Given (1+3+5+7+9+11+13) According to the property of perfect square, for any natural number n, we have sum of first n odd natural numbers = n²But here n = 7 Applying the above law we get

Therefore (1+3+5+7+9+11+13) = 7²= 49

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Without adding, find the sum (1+3+5+7+9+11+13).

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