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Without expanding the determinant, Prove that |[a,a^2, bc],[b,b^2,ca],[c,c^2,ab]|= |[1,a^2,a^3],[1,b^2,b^3],[1,c^2,c^3]| |
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Answer» SOLUTION :L.H.S.`=1/(ABC)|[a^2,a^3,abc],[b^2,b^3,abc],[c^2,c^3,abc]|=1/(abc)(abc)|[a^2,a^3,1],[b^2,b^3,1],[c^2,c^3,1]|=|[a^2,a^3,1],[b^2,b^3,1],[c^2,c^3,1]|` `=|[1,a^2,a^3],[1,b^2,b^3],[1,c^2,c^3]|` (by `C_2 harrC_3`and then by `C_1harrC_2`)=R.H.S. |
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