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Without expandingthe determinant prove the following. |[x,a,x+a],[y,b,y+b],[z,c,z+c]|=0 |
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Answer» Solution :`|[X,a,x+a],[y,b,y+a],[Z,C,z+a]|=|[x+a,a,x+a],[y+b,b,y+b],[z+c,c,z+c]|`(by`C_1rarrC_1+C_2`) `=0(becauseC_1=C_3)` |
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