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Without using trigonometric tables, find the value ofsin210°+sin280sec 20° -cot2 70°12.3 tan 80° tan 50° tan 45° tan 10° tan 40° |
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Answer» sin80° = cos10tan 10°= cot80tan 45° = 1tan40° = cot 50° and sec^theta- tan^2 theta= 1 |
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