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Work done during isothermal expansion of one mole of an ideal gas from 10 atm to 1 atm at 300 K is (Gas constant = 2)A. 938.8 calB. 1138.8 calC. 1381.8 calD. 1581.8 cal

Answer» Correct Answer - C
`-W=+2.303 nRTlog.(P_(1))/(P_(2))`
`-W=2.303xx1xx2xx300log.(10)/(1)=1381.8 cal`.


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