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Work done in increasing the size of a soap bubble from a radius of 3cm to 5cm is nearly (Surface tension of soap solution `=0.03Nm^-1`)A. `0.2pimJ`B. `2pimJ`C. `0.4pimJ`D. `4pimJ` |
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Answer» Correct Answer - C Work done `=` change in surface energy `impliesW=2Txx4pi(R_(2)^(2)-R_(1)^(2))` `=2xx0.03xx4pi[(5)^(2)-(3)^(2)]xx10^(-4)J=0.4pimJ` |
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