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Work of 3.0xx10^(-4) Joule is required to be done in increasing the size of a soap film from 10cmxx6cm to 10cmxx11cm. The surface tension of the film is ……

Answer» <html><body><p>`5xx10^(-2)<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>//m`<br/>`3xx10^(-2)N//m`<br/>`1.5xx10^(-2)N//m`<br/>`1.2xx10^(-2)N//m`</p>Solution :Surface tension T`=("work <a href="https://interviewquestions.tuteehub.com/tag/done-2591742" style="font-weight:bold;" target="_blank" title="Click to know more about DONE">DONE</a>")/("<a href="https://interviewquestions.tuteehub.com/tag/increase-1040383" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASE">INCREASE</a> in <a href="https://interviewquestions.tuteehub.com/tag/area-13372" style="font-weight:bold;" target="_blank" title="Click to know more about AREA">AREA</a>")`<br/> Soap film has two free surface , <br/>`thereforeT=(3.0xx10^(-4)J)/(<a href="https://interviewquestions.tuteehub.com/tag/2xx-1840186" style="font-weight:bold;" target="_blank" title="Click to know more about 2XX">2XX</a>(10xx11-10xx6)xx10^(-4))`<br/>`=3xx10^(-2)(N)/(m)`</body></html>


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