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InterviewSolution
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Write a balanced equatin foe the following reaction: Methance burns in oxygen to from carbon dioixide and water. |
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Answer» This reaction can be written in the from of a word equatin as: Methane + Oxygen `to` Carbon dioxide + Water Now, Formula of methance is `CH_(4)` Formula of oxygen is `O_(2)` Formula of carbon dioxide is `CO_(2)` And, Formula of water is `H_(2)O` Writing the formulae of all the substances in he above word equation, we get: `" "CH_(4) + O_(2) to CO_(2) + H_(2)O` Let us count the number of various atoms in reactans and products : `{:(,"In reactants","In products"),("No. of C atoms:",1,1),("No . of H atoms:",4,2),("No .of O atoms",2,3):}` The number of carbon atoms is equal on both the sides (1 each) but the number of hyfdrogen atoms and oxygen atoms is not equal. There are 4 hydrogen atoms on the left side but only 2 hydrogen atoms on the right side, we multiple `H_(2)O` by 2 and write `2H_(2)O.` Thus, `" "CH_(4)+ O_(2)toCO_(2)+2H_(2)O` Counting the number of various atoms on bothj the sides again, we get: `{:(,"In reactants","In products"),("No. of C atoms:",1,1),("No . of H atoms:",4,2),("No .of O atoms",2,3):}` Only the number of oxygen atoms is equal now. There are 2 oxygen atoms on the left side but 4 on the rihgts aise. To have 4 oxygen atoms on the left side, we multiply `O_(2)` by 2 and write `2O_(2):` `" "CH_(4)+2O_(2)toCO_(2)+2H_(2)O` Let us count the number of various atoms on the two sides once agaon: `{:(,"In reactants","In products"),("No. of C atoms:",1,1),("No . of H atoms:",4,4),("No .of O atoms",4,4):}` This chemical equation contains an equal number of various types of atoms in the reactants and products, so this is a balanced equation. |
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