Write a note on kelvin scale of temperature.

1.	Write a note on kelvin scale of temperature.
Answer» From Charles law V = V₀(1 + αt) …. (1) If t = -273°C, then(1) ⇒ V = V₀(1 - 273/273), V = 0 Volume of gas becomes zero at -273°C theoretically which is shown in the above fig. But practically all known gases become liquids before attaining this temperature (-273°C). From Charles's law, this is the lowest possible temperature. Lord Kelvin made a scale by taking -273°C as lowest temperature. It is called absolute scale of temperature. The lowest temperature is called absolute zero (0K = -273°C). The temperature on the Kelvin scale is called absolute temperate. The width of each degree on the Kelvin scale is equal to the width of each degree on Celsius scale. The relation between Celsius scale temperature (t) & Kelvin scale temperature (T) is given by T = (t + 273) K

Answer»

From Charles law V = V₀(1 + αt) …. (1)

If t = -273°C, then(1) ⇒ V = V₀(1 - 273/273), V = 0

Volume of gas becomes zero at -273°C theoretically which is shown in the above fig. But practically all known gases become liquids before attaining this temperature (-273°C). From Charles's law, this is the lowest possible temperature.

Lord Kelvin made a scale by taking -273°C as lowest temperature. It is called absolute scale of temperature. The lowest temperature is called absolute zero (0K = -273°C). The temperature on the Kelvin scale is called absolute temperate. The width of each degree on the Kelvin scale is equal to the width of each degree on Celsius scale. The relation between Celsius scale temperature (t) & Kelvin scale temperature (T) is given by

T = (t + 273) K

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