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Write any two factors on which internal resistance of a cell depends .The reading on a high resistance voltmer,where a cell is connected across it , is 2.2 V. When the terminals of the cell are also connected to a resistance of 5 `Omega` as shown in the circuit , the voltmeter reading drops to 1.8 V .Find the interval resistance of the cell. |
Answer» Internal resistance of a cell depends upon the following factors : (i) Distance between the electrodes . (ii) The nature of the electrolyte . (iii) The nature of electrodes . Area of the electrodes , immersed in the electrolyte . If area increases , internal resistance decreases . (b) Given : emf of cell , `epsi = 2.2 V , R = 5 Omega , V = 1 . 8 V` `r = ((epsi)/(V) - 1) R implies ((2.2)/(1.8) - 1) xx 5 = ((2.2 - 1.8)/(1.8)) xx 5` `therefore " " r = (0.4)/(1.8) xx 5 = (2)/(1.8) = 1.1 Omega`. |
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