 
                 
                InterviewSolution
 Saved Bookmarks
    				| 1. | Write Arrhenius equation. Derive on expression for temperature variations. | 
| Answer» Arrhenius equation : `K=A.e^(-Ea//RT)` `"or ln K"=lnA-(E_(a))/(RT)` `"pr "log_(10)K=log_(10)K-(E_(a))/(2.303RT)` Arrhenius equation at two different temperatures `log_(10)K_(1)=log_(10)A-(E_(a))/(2.303RT_(1))" ...(1)"` `log_(10)K_(2)=log_(10)A-(E_(a))/(2.303RT_(1))" ...(2)"` Equation (2) - (1) `log_(10)K_(2)-log_(10)K_(1)=-(E_(a))/(2.303RT_(2))+(E_(a))/(2.303RT_(1))` `therefore" "log_(10).(E_(a))/(2.303R)[(1)/(T)-(1)/(T_(2))]` `therefore" "log_(10).(K_(2))/(K_(1))=(E_(a))/(2.303R)[(T_(2)-T_(1))/(T_(1)T_(2))]` | |