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| 1. |
Write chemical equation involved in this experiment. |
| Answer» Ethanoic acid reacts with ethanol in the presence of an acid catalyst and ester, ethyl ethanoate is formed. `underset("Ethanoic acid")(CH_(3)COOH)+underset("Ethanol")(CH_(3)CH_(2))-OH underset("Catalyst")overset("Acid")to underset(("ethyl ethanoate"))(CH_(3))-COO-CH_(2)-CH_(2)+CH_(2)+underset("Water")(H_(2)O)` | |