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Write down the equation of a freely falling body under gravity.

Answer» <html><body><p></p>Solution :(i) Distanced traveled by an object falling for time .t., u = 0 , s = d , a = g<br/> `s = ut + 1/2 at^2` <br/> ` therefore = 1/2 "<a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a>"^2` <br/>Time .t. <a href="https://interviewquestions.tuteehub.com/tag/taken-659096" style="font-weight:bold;" target="_blank" title="Click to know more about TAKEN">TAKEN</a> for an object to <a href="https://interviewquestions.tuteehub.com/tag/fail-982965" style="font-weight:bold;" target="_blank" title="Click to know more about FAIL">FAIL</a> distance .d.. <br/>` t = sqrt((2d)/(g))` <br/>Instantaneous <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> `v_i`of a falling object after elapsed time .t.<br/> ` v_i = sqrt(2gd)` <br/>Instantaneous velocity `v_i`of a falling object that has traveled distance .d.<br/>` v_i = sqrt(2gd)` <br/>(ii) ` u = - 19.6 ms^(-1)` <br/> `u = 9.8 ms^(-2)` <br/> t = 6 sec <br/> height of the building <br/> ` s = ut + 1/2 at^2` <br/> ` = (-19.6 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 6) + 1/2 (9.8)(6)^2 = - 117.6 + 176.4` <br/> s = 58.8 m</body></html>


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