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Write electron configuration, bond order and Magnetic property of Hydrogen (H_(2)) molecule. |
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Answer» SOLUTION :Electron CONFIGURATION : It is formed by the combination of two hydrogen atoms (1s). Total number of electron in ` H_(2)` molecule = 2 In `H_(2)` molecule BMO : `sigma_(1s) and sigma_(1s)^(*)` `THEREFORE e^(-)` configuration of `H_(2)` molecule : `(sigma_(1s))^(2) (sigma_(1s)^(*))^(0)` bond order : BMO : `sigma`(1s) = 2 electron and ABMO : `(sigma_(1s)^(*)) = 0 ` electron `therefore ` Bond order = `(N_(b) - N_(a))/(2) = ((2 - 0))/(2) = 1 ` This MEANS two H atoms are bonded together by a single covalent bond. Magnetic property : In `H_(2)` molecule, no unpair~d electron is present and only electron paired present . `therefore H_(2)` molecule is diamagnetic . |
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