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| 1. |
Write electronic configuration of oxygen molecule and calclate its bond order. |
| Answer» Solution :`KK^(**)sigma2S^(2)SIGMA^(**)2 S^(2) PI 2 PX^(2)=pi2py^(2)py^(**)2pix^(1)=pi^(**)2PY^(1)` BOND Order`=(N_(b)-N_(A))/r=(8-4)/2=2` | |