1.

Write expression for the work done by 1 moleof the gas in each of the following cases : (i) For irreversible expansion of the gas from volume V_(1) to V_(2). (ii) For reversible isothermal expansion of the gas from volume V_(1) toV_(2). (iii)For expansion of the gas into an evaluated vessel. (iv) For reversibleisothermal compression of the gas from pressure P_(1) to P_(2) (v)For adiabatic expansion resulting into changeof temperature from T_(1) to T_(2).

Answer»

Solution :(i)IRREVERSIBLE EXPANSION takes place when external pressure `(P_(ext))` remains constant
`w_("irrev")= - P_("ext") (V_(2)-V_(1))= -P_(ext) DeltaV`
(ii)Reversible expansion takes place when internal pressure is infinitesimally greater than exterhanl pressure `(P_("int")~=P_(ext))` at EVERY stage. Thsu, externalpressurehas to be ADJUSTED throughout.
`w_(rev)= -nRT LN. (V_(2))/(V_(1))`
(iii) The expansion is irreversible. Further, as `P_(ext) =0`, therefore,
`w= -P_(ext)DeltaV= 0 xx ( DeltaV) = 0`
(iv) When gas is compressed, work is done on the gas. For isothermalreversible compression,
`w= + nRT ln. (P_(2))/(P_(1))`
(v) For adiabatic expansion, temperature falls, i.e.,`T_(2) ltT_(1))`
`w=C_(v) (T_(2)-T_(1)),i.e., w` is -ve.


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