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Write ionization reaction of diprotic acid in aqueous solution. |
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Answer» Solution :SUPPOSE, `H_2A` is DIPROTIC acid. So, its (i) First ionization (ii) second ionization and (iii) COMPLETE ionization equilibrium is as under. (i)`H_2A_((AQ))+H_2O_((l)) hArr HA_((aq))^(-) + H_3O_((aq))^(+)` (ii)`HA_((aq))^(-) + H_2O_((l)) hArr A_((aq))^(2-) + H_3O_((aq))^(+)` (iii)`H_2A_((aq)) + 2H_2O_((l)) hArr A_((aq))^(2-) + 2H_3O_((aq))^(+) ` Here , (iii) = (i)+(ii) |
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