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Write Lewis strcutrue of the following compounds and show formal charge on each atom : HNO_(3), NO_(2), H_(2) SO_(4) |
Answer» Solution :![]() Formal charge = `V - L - (1)/(2) S` Formal chargeon H = ` 1 - 0 - (1)/(2) XX 2 = 0 ` Formal charge on `O (1) = 6 - 4 - (1)/(2)(4 ) = 0 ` formal chargeon (1) `N = 5 - 0 - (1)/(2) (8) = 1` Formal charge on ` O(2) = 6 - 4 - (1)/(2) (4) = 0 ` Formal chargeon `O (3) = 6 - 6 - (1)/(2) (2) = - ` Hence , we write the structure of `HNO_(3)` with write structrue of `HNO_(3)` formal CHARGES as ![]() Similary, we have
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