Write Lewis structure of O_(2)^(-)ion and find out oxidation state of each oxygen atom? What is the average oxidation state of oxygen in this ion?

Write Lewis structure of O_(2)^(-)ion and find out oxidation state of

1.	Write Lewis structure of O_(2)^(-)ion and find out oxidation state of each oxygen atom? What is the average oxidation state of oxygen in this ion?
Answer» Solution :The Lewis STRUCTURE of `O_(2)^(-)` is`:underset(..)overset(..)O-overset(..)O overset("ϴ"):`. Oxygen atom having NOCHARGE has 6 electrons so its oxidation number is zero, but the other oxygen atom CARRYING -1 charge has 7 electronsso its oxidation number is -1. Hence, the average oxidation state of oxygen is `-(1)/(2)`.