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Write Lewis structure of `O_(2)^(-)` ion and find out oxidation state of each oxygen atom ? What is the average oxidation state of oxygen in this ion ?

Answer» The Lewis structure of `O_(2)^(-)` is `:overset(.)underset(..)(O)- underset(..)overset(..)(O):-. `
Since O atom carrying no charge has six electrons and hence its O.N. is zero but O atom carrying negative charge has seven electrons and hence its O.N. is `-1` . Therefore , average O.N. of each O = 1/2 (0+1) = 1/2.


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