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Write Nernst equation for single electrode potential. |
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Answer» Solution :For the ELECTRODE reaction, `M^(N+)//n e^(-)TOM` `E_(M^(N+)//M)=E_(M^(n+)//M)^(@)-(2.303RT)/(nF)"log"([M])/([M^(n+)])=E_(Mn^(2+)//M)^(@)-(2.303RT)/(nF)"log"(1)/([M^(n+)])`. |
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