Write of the following have identical bond order ? CN^(-), O_(2)^(-) , NO^(+) and CN^(+)

Write of the following have identical bond order ? CN^(-), O_(2)^(-) ,

1.	Write of the following have identical bond order ? CN^(-), O_(2)^(-) , NO^(+) and CN^(+)
Answer» Solution :Total no. of electrons in `CN^(-) = 6 + 7 + 1 = 14` Total no. of electrons in ` O_(2)^(-) + 8 + 8+ 1 = 17` Total no. of electrons in ` NO^(+) + 7 + 8 -1 = 14` Total no. of electrons in `CN^(+) = 6 + 7 - 1 = 12 ` As ` CN^(-) and NO^(+)` have the same BOND order .