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Write oxidation number of .C. in acetic acid. |
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Answer» Solution :`CH_(3)COOH:CH_(3)-overset(O)overset(||)(C)-O-H` Oxidatio number of ALKYL group which is attached to CARBONYL group will be zero. `(CH_(3))+1(C)+2(O)+1(H)=0` `therefore0+C+2(-2)+(+1)=0` `thereforeC=+3` |
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