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Write oxidation number of oxygen in KO_(3)andNa_(2)O_(2). |
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Answer» SOLUTION :`KO_(3)rArr1(K)+3(O)=0` `therefore1(+1)+3(O)=0` `thereforeO=-1/3` `Na_(2)O_(2)rArr2(NA)+2(O)=0` `therefore2(+1)+2(O)=0` `therefore2+2(O)=0` `thereforeO=-1` |
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