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Write preparation of : (i) Xenon - Fluorine compounds (ii) Xenon - Oxygen compounds |
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Answer» Solution :Xenon - Fluorine compounds : Xenon forms three binary fluorides, `XeF_2, XeF_4` and `XeF_6` by the direct reaction of ELEMENTS under appropriate experimental conditions. `UNDERSET("excess")(Xe(g)) + F_(2)(g) overset(673 K, 1bar)to XeF_(2)(s)` `underset(1:5 "ratio")(Xe(g) + 3F_(2)(g) overset(573 K)/(50-70 "BAR")to XeF_(6)(s)` `XeF_6` can also be prepared by the interaction of `XeF_4` and `O_(2)F_(2)` at 143 K. `XeF_(4) + O_(2)F_(2) to XeF_(6) + O_(2)` Xenon-Oxygen compounds : Hydrolysis of `XeF_4` and `XeF_6` with water gives `XeO_(3)` `6XeF_(4) + 12H_(2)O to 4Xe + 2XeO_(3) + 24HF + 3O_(2)` `XeF_(6) + 3H_(2)O to XeO_(3) + 6HF` Partial hydrolysis of `XeF_6` gives oxyfluorides, `XeF_(6) + H_(2)O to XeOF_(4) + 2HF` `XeF_(6) + 2H_(2)O to XeO_(2)F_(2) + 4HF` |
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