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Write reaction for autoprotolysis of water. How is ionic product of water related to ionization constant of water ? Derive the relationship. |
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Answer» SOLUTION :Autoprotolysis of `H_(2)O` TAKES place as : `{:(H_(2)O+H_(2)O,HARR,H_(3)O^(+)+OH^(-)),(""H_(2)O,hArr,H^(+)+OH^(-)):}` For IONIZATION of `H_(2)O`, `K_(i)=([H^(+)][OH^(-)])/([H_(2)O])=(K_(w))/([H_(2)O])=(K_(w))/(55.55 "mol" L^(-1)) or K_(w)=K_(i)xx55.55`. |
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