Write structure and IUPAC names of (i) The amide which gives propanamide by Hofmann bromamide reaction. (ii) the amine produce by the Hofmann degradation of benzamide.

Write structure and IUPAC names of (i) The amide which gives propanam

1.	Write structure and IUPAC names of (i) The amide which gives propanamide by Hofmann bromamide reaction. (ii) the amine produce by the Hofmann degradation of benzamide.
Answer» Solution :(i). PROPANAMINE CONTAINS three carbon atoms, therefore, the amide molecule must contain four carbon atoms. THUS, the structure and IUPAC name of the amide containing four carbon atoms is `UNDERSET("Butanamide")(CH_(3)-CH_(2)-CH_(2)-overset(O)overset(\|\|)(C)-NH_(2))`. The complete reaction is `underset("Butanamide")(CH_(3)CH_(2)CH_(2)CONH_(2))+ Br_(2)+4KOH overset(Delta)to underset("Propan-1-amine")(CH_(3)CH_(2)CH_(2)-NH_(2))+ 2KB r+K_(2)CO_(3)+2H_(2)O` (ii) Benzamide is an aromatic amide containing seven carbon atoms. therefore, the amine FORMED from benzamide is aromatic primary amine containing six carbon atom, i.e., The complete reaction is ltBrgt .