1.

Write the atomic number of the element present in the third and seventeenth group of the periodic table.

Answer»

Solution :Since it belongs to 3RD period, it will have outermost shell , n = 3.
It.s configuration will be `3s^(2)3p^(5)`.
`:.{:(He,Ne,Ar),(2,10,18):}`
` :. ` atomic number `(Z = 10 + 2 + 5) = 17`
` :. ` element Cl (Chlorine)


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