1.

Write the balanced equations for the following reactions:KCN + H2SO4 → K2SO4 + HCN

Answer»

Step 1:

Rewrite the given equation as it is

KCN + H2SO4 → K2SO4 + HCN

Step 2:

Write the number of atoms of each element or group in the unbalanced equation on both sides of the equation.

ElementNumber of atoms in reactantsNumber of atoms in products
K12
CN (group)11
O44
H44
S11

The number of oxygen atoms involved in different compounds on both sides (reactants and products) are equal. Therefore, balance the number of atoms of the second element, potassium.

Step 3:

To balance K atoms:

Number of atoms of PotassiumIn reactantsIn products
To begin with2 (KCN)2 (in K2SO4)
To balance1 × 22

To equalise the number of potassium atoms, we use 2 as the coefficient of KCN in the reactants. 

Now, the partly balanced equation becomes 

2KCN + H2SO4 → K2SO4 + 2HCN

Now, count the atoms of each element on both sides of the equation. The number of atoms on both sides are equal. Hence, the balanced equation is

2KCN + H2SO4 → KgSO4 + 2HCN

Now indicate the physical states of the reactants and the products.

2KCN(aq) + H2SO4(aq) → K2SO4(aq) + 2HCN(g)

2KCN + H2SO4 → K2SO4 + 2HCN


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