1.

Write the balanced equations for the following reactions:Ba(OH)2 + HBr → BaBr2 + H2O

Answer»

Step 1:

Rewrite the given equation as it is 

Ba(OH)2 + HBr → BaBr2 + H2O

Step 2:

write the number of atoms of each element in the unbalanced equation on both sides of the equation.

ElementNumber of atoms in reactantsNumber of atoms in products
Ba11
Br12
O21
H32

Step 3:

To balance the number of oxygen atoms:

Number of atoms of oxygenIn reactantsIn products
To begin with2 [in Ba(OH)2]1 (in H2O)
To balance21 × 2

To equalise the number of oxygen atoms, we use 2 as the coefficient of H2O in the product.

Now, the partly balanced equation become as follows

Ba(OH)2 + HBr → BaBr2 + 2H2O

Step 4:

Now, balance the number of hydrogen atoms. In the partly balanced equation:

Number of atoms of oxygenIn reactantsIn products
To begin with2 [in Ba(OH)2] 1 (in HBr)4 (in 2H2O)
To balance1 × 2 + 24

To equalise the number of hydrogen atoms, we use 2 as the coefficient of HBr in the reactants. Now, the equation becomes

Ba(OH)2 + 2HBr → BaBr2 + 2H2O

Now, count the atoms or each element on both sides of the equation. The number of atoms on both sides are equal. Hence, the balanced equation is

Ba(OH)2 + 2HBr → BaBr2 + 2H2O

Now indicate the physical states of the reactants and products.

Ba(OH)2(aq) + 2HBr(aq) → BaBr2(aq) + 2H2O(l)


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