Write the cell reaction and calculate Eº cell of the followingelectro

1.	Write the cell reaction and calculate Eº cell of the followingelectrochemical cell:AllAl3+\|\|Zn2+Izn(s) (aq.) (aq.) (s)(1M) (IM)E°al = -1.66VE°zn= – 0.76V
Answer» GIVEN that, Cell potential of Al $E^{o}_{Al}=-1.66\ V$ Cell potential of ZN $E^{o}_{Zn}=-0.76\ V$ We KNOW that, Zinc is anode and silver is cathode. We NEED to calculate the cell potential E⁰ Using formula of cell potential $E^{o}_{cell}=E^{o}_{cathod}-E^{o}_{anode}$ Where, $E^{o}_{cathod}$ = cell potential of Al $E^{o}_{anode}$ = cell potential of Zn Put the value into the formula $E^{o}_{cell}=-1.66-(-0.76)$ $E^{o}_{cell}=-0.9\ V$ Hence, The cell potential E⁰ is -0.9 V.