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Write the cell reaction and caleulate the e.m.f of the following cell at 298 K: Sn (s) // [Sn^(2+) (0.004 M) || H^+ (0.020) M] / /H_2 (g) (I bar) | Pt (s) |
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Answer» SOLUTION :`Sn^+ 2H+ to Sn^(2+) + H_2` (EQUATION must be BALANCED) `E=E^@ 0.059/.2 LOG ([Sn^(2+)])/([H^+]^2)` `=[0(-0.14)]-0.0295 log ((0.004))(0.02)^2` |
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