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Write the cell representation and calculate equilibrium constant for the following redox reaction : `Ni_((s))+2Ag_((aq))^(+)(1M) to Ni_((aq))^(2+)(1M) to 2Ag_((s)) at 25^(@)C` `E_(Ni)^_(Ni)^(2+)(@)=0*25V and E_(Ag)(+)^(@)=0*799V` |
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Answer» `Ni_((1M))^(2+)//Ni||Ag^(+)(1M)||Ag` `E_("cell")^(@)=(0*0592)/(n)log_(10)K` `E_("Cell")^(@)=E_(Ag)^(@)-E_(Ni)^(@)` `=0*799(V)-(-0*25)=1*049V` `:. =1*048=(0*0592)/(2)log_(10)K` `1*049=(0*0592)/(2)log_(10)K` `log_(10)K=(1*049xx2)/(0*0592)` `=35*44` `K="antilog"=35*4=2*754xx10^(23)` |
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