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If the angular speed of the Earth is `7.26xx10^(-5)` rad/s and radius of the Earth is 6,400 km, calculate the change in weight of 1 kg of mass taken from equator to pole. |
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Answer» Given, angular speed of Earth `(omega)=7.26xx10^(-5)` rad/s radius of earth (R) `=6400km=6.4xx10^(6)m` mass of body (m)=1 kg At poles, `phi=90^(@)` `:.cos90^(@)=0` Now, Change in weight `(DeltaW)=mDeltag` `=m(Romega^(2))` `=1xx6.4xx10^(6)xx(7.26xx10^(-5))^(2)` `=3.373xx10^(-2)N |
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