1.

Write the coefficient of x2 in each of the following: (i) 17 – 2x + 7x2 (ii) 9 – 12x + x3 (iii) \(\frac{\pi}{6} x^2 - 3x + 4\)(iv) √3x – 7

Answer»

(i) 17 – 2x + 7x2

Coefficient of x2 = 7 

(ii) 9 – 12x + x3 

Coefficient of x2 =0 

(iii)  \(\frac{\pi}{6} x^2 - 3x + 4\) 

Coefficient of x2 = \(\frac{\pi}{6}\) 

(iv) √3x – 7 

Coefficient of x2 = 0



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