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Write the condition under which three numbers a, b, c may be in Aand G.P. both. |
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Answer» If we consider a set of three numbers a, b and c which are in AP, we know that a + c =2b. Now, if they are in GP, a*c =b^2. Now we have to see if it is possible to have three numbers satisfy both the equations. If we express a as 2b - c and replace it in a*c = b^2, it gives us (2b-c)*c = b^2 => 2bc – c^2 = b^2 => b^2 + c^2 – 2bc =0 => (b-c) ^2 =0 => b = c Also, as a = 2b-c = 2c-c = c we find that all the three number have to be equal. So a set of three numbers which are in AP as well as GP are a set of three equal numbers. |
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