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Write the cubes 5 natural numbers of the from 3n+2 (i.e.5,8,11….) and verify the following:“The cube of a natural number of the form 3n+2 is a natural number of the same form i. e. when it is dividend by 3 the remainder is 2’ |
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Answer» First 5 natural numbers in form ( 3n + 2 ) are = 5 , 8 , 11 , 14 , 17 Cubes of these numbers are, = 53 = 5 × 5 × 5 = 125 = 83 = 8 × 8 × 8 = 512 = 113 = 11 × 11 × 11 = 1331 = 143 = 14 × 14 × 14 = 2744 = 173 = 17 × 17 × 17 = 4313 We find that all these cubes give remainder 2 when divided by 3.. Hence statement is true. |
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