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Write the derivative of `sinx`w.r.t. `cosxdot` |
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Answer» We know that `dy/dz` can be written as`dy/dz = (dy/dx) / (dz/dx)`. So. here,` y=sinx` and `z = cosx`. `:. dy/dx = cosx ` ` dz/dx = -sinx ` `:.dy/dz = (dy/dx) / (dz/dx) = cosx/(-sinx)= -cotx` `:. dy/dz =-cotx` |
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