1.

Write the derivative of `sinx`w.r.t. `cosxdot`

Answer» We know that `dy/dz` can be written as`dy/dz = (dy/dx) / (dz/dx)`.
So. here,` y=sinx` and `z = cosx`.
`:. dy/dx = cosx `
` dz/dx = -sinx `
`:.dy/dz = (dy/dx) / (dz/dx) = cosx/(-sinx)= -cotx`
`:. dy/dz =-cotx`


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