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Write the difference between maximum and minimum values of sin–1x for x ∈ [–1, 1]. |
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Answer» Let f (x) = sin-1 x For x to be defined, -1 ≤ x ≤ 1 For -1 ≤ x ≤ 1, sin-1(-1) ≤ sin-1 x ≤ sin-1(1) ⇒ -π/2 ≤ sin-1 x ≤ π/2 ⇒ -π/2 ≤ f (x) ≤ π/2 Maximum value = π/2 and minimum value = -π/2 ∴ The difference between maximum and minimum values of sin-1 x = π/2 – (-π/2) = 2π/2 = π |
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