1.

Write the difference between maximum and minimum values of sin–1x for x ∈ [–1, 1].

Answer»

Let f (x) = sin-1 x

For x to be defined, -1 ≤ x ≤ 1

For -1 ≤ x ≤ 1, sin-1(-1) ≤ sin-1 x ≤ sin-1(1)

⇒ -π/2 ≤ sin-1 x ≤ π/2

⇒ -π/2 ≤ f (x) ≤ π/2

Maximum value = π/2 and minimum value = -π/2

∴ The difference between maximum and minimum values of

sin-1 x = π/2 – (-π/2) = 2π/2 = π



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