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Write the dimensions of a and b in the relation ,` P = (b-x^(2))/(at)` , where P is power ,x is distance and t is timeA. `[M^0 lT^(-2)]`B. `[M^0L^2 T^2]`C. `[M^0 L^2 T^(-2)]`D. `[M^0 L^2 T^0]` |
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Answer» Correct Answer - (d) As `x^2` is subtracted from b, therefore, dimensional formula of `b = x^2 = L^2 = [M^0 L^2 T^0]` |
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