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Write the electronic configuration and find the no. of unpaired electrons as well as total spin for the following atoms: (i) _(6)C (ii) _(8)O (iii) _(15)P (iv) _(21)Sc (v) _(26)Fe (vi) _(10)Ne |
Answer» Solution : `THEREFORE` No. of UNPAIRED electrons = 2 `therefore` TOTAL spin `=(+2)/(2)` or `(-2)/(2)` `[Ar] 3d^(1)4S^(2)` `therefore`No. of unpaired electrons = 1 `theredore` Total spin `=(+1)/(2)` or `(-1)/(2)`
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