1.

Write the electronic configuration of Ce^(4+) and Co^(2+),

Answer»

Solution :`Ce (Z = 58) toCe^(4+) 4e^(-)`
`Ce^(4+)- 1s^(2)2S^(2)2P^(6)3s^(2)3p^(6)4s^(2)3d^(10)4p^(6)5s^(2)4d^(10)5p^(6)`
`Co^(2+)- 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(5)`


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