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Write the electronic configuration of O_(2) molecule in the singlet state. |
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Answer» Solution : Ordinary ` O_(2)`moleucle has the electronic configuration `sigma_(1s)^(2) sigma_(1s)^(**2) sigma_(2s)^(2) sigma_(2p_(z))^(**2).pi_(2P_(x))^(2)pi_(2P_(y))^(2)pi_(2P_(x))^(**1)pi_(2P_(y))^(**2)` Multiplicity= (2S + 1 ) Where S =total electron spin ` = 2 ((1)/(2) + (1)/(2)) + 1 = 3 ` ""` [ S = (1)/(2) + (1)/(2) ` because two electons have parallel spins] Hence , it is in the triplet STATE if two ELECTRONS pair up ` S = (1)/(2) - (1)/(2) = 0 ` (because they will have opposite spin) Spin multiplicity = `2S + 1 = 0 + 1 = 1 ` This is called singlet state . Hence, electronic configuration of `O_(2)` moleculein the single state will be `sigma_(1s)^(2) sigma_(1s)^(**2) sigma_(2s)^(2) sigma_(2s)^(**2)sigma_(2p_(z))^(2).pi_(2P_(x))^(2)pi_(2P_(y))^(2)pi_(2P_(x))^(**2)pi_(2P_(y))^(**0)` |
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