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Write the electronic configuration of O2 molecule and calculate its bond order based on MOT. |
Answer» KK(σ2s)2 (σ*2s)2 σ2pz 2 (π2px2 = π2py2)(π *2px‟= π*2py‟) Bond order= ½[Nb-Na] = ½[10-6] = 2 |
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