1.

Write the electronic configuration of O2 molecule and calculate its bond order based on MOT.

Answer»

KK(σ2s)2 (σ*2s)2 σ2pz 2 (π2px2 = π2py2)(π *2px‟= π*2py‟)

Bond order= ½[Nb-Na]

= ½[10-6]

= 2 



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