1.

Write the electronic configuration of the elements with Z=17 and predict (i) no. of p electrons (ii) no. of filled orbitals (iii) no. of half filled orbitals ?

Answer» The element with Z=17 is chlorine. Its electronic configuration is : `1s^(2)2s^(2)2p^(6)3s^(2)3p_(x)^(2)3p_(y)^(2)3p_(z)^(1)`
(i) No. of p electrons=11 , (ii) No. of filled orbitals=8, (iii) No. of half filled orbitals =1.


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