1.

Write the equation of the point circle with centre at (a) (4, -5) (b) (-3, 2) (c) (1,0).

Answer»

(a) Point circle means circle whose radius = 0 

Given C = (4,-5) & r = 0 

The point circle & (x – 4)2 + (y + 5)2 = 0 

⇒ x2 + y2 – 8x + 10y + 41 = 0 

(b) Centre (-3,2) 

The point circle is (x + 3)2 + (y – 2)2 = 0 

⇒ x2 + y2 + 6x – 4y + 13 = 0 

(C) Centre (1,0) 

∴ Circle is (x – 1)2 + (y – 0)2 = 0 

x2 – 2x + 1 + y2 = 0 

⇒ x2 + y2 – 2x + 1 = 0.



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