Write the factors of ihe polynomial 4x²+y²+4+4xy+8x+4y

1.	Write the factors of ihe polynomial 4x²+y²+4+4xy+8x+4y
Answer» 4x² + y² + 4xy + 8x + 4y = 4² + 4xy + y² + 8x + 4y + 4 =[(2x)² + 2 × (2x) (y) + (y)²] + 4 (2x + y ) + 4 = a² + 4a + 4 =a² + 2a + 2a + 4 = a (a+2) + 2 (a + 2 )=(a + 2) (a + 2 ) = (a + 2)²= ( 2x + y + 2 )² Thus, 4x² + y² + 4xy + 8x + 4y + 4 = ( 2x + y + 2 )²

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