Write the folllowing redox rections using half equations (i) Zn(s) + PbCI_(2)(aq) rarr Pb(s)+ZnCI_(2)(aq) (ii)2Fe^(3+)(aq)+2I^(-)(aq)rarrI_(2)(s)+2 Fe^(2+)(aq) (iii)2Na(s)+CI_(2)(g)rarr2 NacI(s) (iv)Mg(s)+CI_(2)(g)rarrMgCI_(2)(s) (v)Zn(s)+2H^(+)(aq) rarr Zn^(2+)(aq)+H_(2)(g) In each of the reactions gien above mention (a) Which reactant is oxidized ?to what ?(b) which reactant is hte oxidiser ? (c )which reactant is reduced ? To what ?(d) which reactant is hte reducer?

Write the folllowing redox rections using half equations (i) Zn(s) +

1.	Write the folllowing redox rections using half equations (i) Zn(s) + PbCI_(2)(aq) rarr Pb(s)+ZnCI_(2)(aq) (ii)2Fe^(3+)(aq)+2I^(-)(aq)rarrI_(2)(s)+2 Fe^(2+)(aq) (iii)2Na(s)+CI_(2)(g)rarr2 NacI(s) (iv)Mg(s)+CI_(2)(g)rarrMgCI_(2)(s) (v)Zn(s)+2H^(+)(aq) rarr Zn^(2+)(aq)+H_(2)(g) In each of the reactions gien above mention (a) Which reactant is oxidized ?to what ?(b) which reactant is hte oxidiser ? (c )which reactant is reduced ? To what ?(d) which reactant is hte reducer?
Answer» Solution :(i) `ZN(s) rarr Zn^(2+)+2e^(-) ("oxidation") , Pb^(2+)(aq)+2e^(-) rarrPb(s)("REDUCTION")` Zn is oxidised to `Zn^(2+), Pb^(2+) ("reduction"), Pb^(2+)` is the oxidiser and Zn is the REDUCER (ii) `2Fe^(3+)+2e^(-) rarr 2Fe^(2+) ("reduction"), 2I^(-)rarrI_(2)+2e^(-)("oxidation")` `Fe^(3+)` reduced to `Fe^(2+) I^(-)` is oxidiased to `I_(2), I^(-)` is the reducer and `Fe^(3+)` is the oxidiser (iii)`2Na rarr2Na^(+)+2e^(-)("oxidation"), CI_(2)+2e^(-)rarr2CI^(-)`(reduction) Na is oxidised to `Na^(+) "and" CI_(2)` is reduced to `CI^(-), CI_(2)+2e^(-) rarr 2CI^(-)` (reduction ) Mg is oxidised o `Zn^(2+)` while `H^(+)` is reduced to `H_(2)`, Zn is ht reducer and `H^(+)` is the oxidiser